daft.Expression.dt.year#

Expression.dt.year() → Expression[source]#

Retrieves the year for a datetime column

Example

>>> import daft, datetime
>>> df = daft.from_pydict({
...         "datetime": [
...             datetime.datetime(2024, 7, 3, 0, 0, 0),
...             datetime.datetime(2023, 7, 4, 0, 0, 0),
...             datetime.datetime(2022, 7, 5, 0, 0, 0),
...         ],
...     }
... )
>>> df.with_column("year", df["datetime"].dt.year()).collect()
╭───────────────────────────────┬───────╮
│ datetime                      ┆ year  │
│ ---                           ┆ ---   │
│ Timestamp(Microseconds, None) ┆ Int32 │
╞═══════════════════════════════╪═══════╡
│ 2024-07-03 00:00:00           ┆ 2024  │
├╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
│ 2023-07-04 00:00:00           ┆ 2023  │
├╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
│ 2022-07-05 00:00:00           ┆ 2022  │
╰───────────────────────────────┴───────╯

(Showing first 3 of 3 rows)

Returns:: a UInt32 expression with just the year extracted from a datetime column
Return type:: Expression

daft.Expression.dt.year

Contents

daft.Expression.dt.year#